(1/25)^(2x+2)=125^x

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Solution for (1/25)^(2x+2)=125^x equation: 



(1/25)^(2x+2)=125^x

We move all terms to the left:

(1/25)^(2x+2)-(125^x)=0



Domain of the equation: 25)^(2x+2)!=0

x∈R



We add all the numbers together, and all the variables

(+1/25)^(2x+2)-125^x=0

We multiply all the terms by the denominator


(+1-125^x*25)^(2x+2)=0

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